PCh7 Lec4

3D Rotation (Sec 7.3)

Okay, just like every other quantum system that we have been working with, we must define the Hamiltonian operator (total energy operator), find an acceptable solution for the eigenfunctions, and then determine the eigenvalues (total energy). Because we are working in 3D, it is not real convenient to use x, y, and z, so like 2D rotation, we are shifting over to define the system in terms of spherical polar coordinates (spc).

At this stage of QM, we introduce a new term called the Laplacian, an upside down triangle;

Note that the entire Schrodinger Equation is shown in your text in eq. 7.17. Spend a little time comparing eq. 7.17 to the Hamiltonian equation above...note to following:

- the 1/r^2 has been factored out of the expression in eq. 7.17,

- "m" has been replaced with "μ" the reduced mass in eq. 7.17, and

- the potential energy term is zero.

Your text continues with a short discussion of how one might solve for the eigenvalues; this discussion involves the "separation of variables," which means instead of having one function Υ(θ, φ) dependent on both θ and φ, we now have a function that is a product of θ and φ, Θ(θ)*Φ(φ) (see eq. 7.20). Your text does not go into much more detail before providing you with the solution to the eigenfunction, the "spherical harmonics." Like the previous 2D rotation solution was given to you as the Hermite polynomials, hereto the solution is just stated to be the spherical harmonics.

Some important issues come out of this discussion: 1) The 3D rotation solution is kind of like the 2D + 1D. In the 2D solution, the integer (ie soon to be called quantum number), m_l = 0, ±1, ±2, ±3, ..., so the 3D solution contains this integer as well as one more, l = 0, 1, 2, 3, ... 2)