Difference between revisions of "ESR Lab Activity"
Jump to navigation
Jump to search
| Line 9: | Line 9: | ||
(enter a table here with information, molar mass, sigma product number, cost) | (enter a table here with information, molar mass, sigma product number, cost) | ||
| + | |||
| + | {| | ||
| + | ||Name | ||
| + | ||Molar Mass | ||
| + | ||Sigma Product Number | ||
| + | ||Cost | ||
| + | |- | ||
| + | || | ||
| + | || | ||
| + | || | ||
| + | || | ||
| + | |- | ||
| + | || | ||
| + | || | ||
| + | || | ||
| + | || | ||
| + | |- | ||
| + | || | ||
| + | || | ||
| + | || | ||
| + | || | ||
| + | |} | ||
==Experimental== | ==Experimental== | ||
Revision as of 19:44, 21 April 2016
Introduction
We are going to collect an ESR spectrum from a series of substituted hydroquinones.
- A=Hydroquinone (110.11 g/mol)
- B=methylhydroquinone (124.14 g/mol)
- C=2,3-dimethylhydroquinone (138.16 g/mol)
(enter a table here with information, molar mass, sigma product number, cost)
| Name | Molar Mass | Sigma Product Number | Cost |
Experimental
Beaker Method
- Solution A: 1 M NaOH; 1 gram NaOH (39.997 g/mol) into 25 mL EtOH.
- Solution B: 1 M hydroquinone solution.
- Procedure: To 2 ml of 1 M hydroquinone solution add 2-3 drops of solution A. A color change will indicate the reaction has occurred. Quickly transfer colored sample to ESR sample tube, place in ESR spectrometer, tune, and collected data.
Flow Method
- Solution A: 0.05 M NaOH; 0.05 grams NaOH (39.997 g/mol) into 25 ml EtOH.
- Solution B: 1 M hydroquinone solution.
- Procedure: Prepare two syringed with