Difference between revisions of "Particle in a Box"

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===Initial Tasks===
 
===Initial Tasks===
 
1) Convince yourself that the function provided above is an eigenfunction of the Hamiltonian operator.
 
1) Convince yourself that the function provided above is an eigenfunction of the Hamiltonian operator.
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:You ask, how do i do that?...just operate on the function with the Hamiltonian operator and if you return a "value" and the function, then the function is an eigenfunction for the Hamiltonian operator. You do need to know that the potential energy, V(x), inside of the box is equal to zero...so the Hamiltonian operator is a bit more simple in this model system. '''Please "do this" work in your lab notebook.
  
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2) Notice that although this function is an eigenfunction of the Hamiltonian operator, there may be other solutions...any ideas?
 +
:Please plot this function in Mathematica..
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:Note: Boundary conditions y(0) = 0 and y(a) = 0
  
The Chemical System:
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===The Chemical System===
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===Data Collection===

Revision as of 14:23, 9 February 2017

Question: Can a simple function like y(x) = A*Sin[Pi*x/a] describe an electron in a molecule?

Answer: yes.

The Basic Model System

1) Consider a box with no lid with infinitely high walls. This box represents the "molecular frame" for which the electron can exist.

2) When a particle/electron is placed inside this box, it has a particular "energy." Considering that "energy" is a measurable quantity in systems described by classical mechanics, Q.M. postulate 2 tells us that there exists a corresponding operator that can be used to predict the energy or as we say this observable.

3) As with all "operator algebra" problems, there are 3 parts:

- the operator
- the (eigen)function
- the eigenvalue = observable.

The operator in this case, like many, is the Hamiltonian operator, the eigenfunction is given above, and we need to solve for the eigenvalue or energy.

Initial Tasks

1) Convince yourself that the function provided above is an eigenfunction of the Hamiltonian operator.

You ask, how do i do that?...just operate on the function with the Hamiltonian operator and if you return a "value" and the function, then the function is an eigenfunction for the Hamiltonian operator. You do need to know that the potential energy, V(x), inside of the box is equal to zero...so the Hamiltonian operator is a bit more simple in this model system. Please "do this" work in your lab notebook.

2) Notice that although this function is an eigenfunction of the Hamiltonian operator, there may be other solutions...any ideas?

Please plot this function in Mathematica..
Note: Boundary conditions y(0) = 0 and y(a) = 0


The Chemical System

Data Collection