Difference between revisions of "PChem312 f20 w13"
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1) Reversible Isothermal Expansion or Compression | 1) Reversible Isothermal Expansion or Compression | ||
− | :V<sub>i</sub>T<sub>i</sub>-->V<sub>f</sub>T<sub>i</sub> | + | :::V<sub>i</sub>T<sub>i</sub>-->V<sub>f</sub>T<sub>i</sub> |
2) Constant P, V temperature change | 2) Constant P, V temperature change | ||
− | :V<sub>i</sub>T<sub>i</sub>-->V<sub>i</sub>T<sub>f</sub> | + | :::V<sub>i</sub>T<sub>i</sub>-->V<sub>i</sub>T<sub>f</sub> |
− | :P<sub>i</sub>T<sub>i</sub>-->P<sub>i</sub>T<sub>f</sub> | + | :::P<sub>i</sub>T<sub>i</sub>-->P<sub>i</sub>T<sub>f</sub> |
3) Changes in both V and T, constant P | 3) Changes in both V and T, constant P | ||
− | :V<sub>i</sub>T<sub>i</sub>-->V<sub>f</sub>T<sub>f</sub> | + | :::V<sub>i</sub>T<sub>i</sub>-->V<sub>f</sub>T<sub>f</sub> |
4) Changes in both P and T, constant V | 4) Changes in both P and T, constant V | ||
− | :V<sub>i</sub>T<sub>i</sub>-->V<sub>f</sub>T<sub>f</sub> | + | :::V<sub>i</sub>T<sub>i</sub>-->V<sub>f</sub>T<sub>f</sub> |
====Example Problem 1==== | ====Example Problem 1==== |
Revision as of 14:53, 9 November 2020
Monday, Nov 9, 2020
We will now highlight how to calculate entropy (ΔS) for four processes involving ideal gases:
1) Reversible Isothermal Expansion or Compression
- ViTi-->VfTi
2) Constant P, V temperature change
- ViTi-->ViTf
- PiTi-->PiTf
3) Changes in both V and T, constant P
- ViTi-->VfTf
4) Changes in both P and T, constant V
- ViTi-->VfTf
Example Problem 1
- (Please write out your complete solution and email to bes by next class period)
Consider a gas undergoing the following change under constant pressure (1.00 bar) conditions; calculate the change in entropy (ΔS): Vi = 10.0 L; Ti = 298 K; Tf = 398 K
Example Problem 2
- (Please write out your complete solution and email to bes by next class period)
Consider a gas undergoing the following change under constant volume (10.0 L) conditions; calculate the change in entropy (ΔS): Pi = 1.00 bar; Ti = 298 K; Tf = 398 K