Difference between revisions of "Free Radical Generation"

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===3. Fenton Chemistry===
 
===3. Fenton Chemistry===
[[Media: Fenton.pdf|Fenton Chemistry Article]]
+
References
 +
:[[Media: Fenton.pdf|Fenton Chemistry Article]]
 +
:[[Media:Water_Res_2016.pdf|Fenton/DMPO (2016)]]
 +
:[Media:1-s2.0-S0891584996004327-main.pdf|Mason (1997) Fenton/DMPO]]
  
 
Fe2+    +    H2O2  --->    OH•    +    phenol    --->      phenoxyl radical
 
Fe2+    +    H2O2  --->    OH•    +    phenol    --->      phenoxyl radical

Revision as of 19:19, 6 June 2019

The 1-electron oxidation of a phenol can be accomplished via chemical or enzymatic means.

Chemical Means

1. KMnO4

KMnO4

To make a 2 mM solution of KMnO4, we added 0.0316g of KMnO4 solid to 100 mL dH2O

To make a 2 mM solution of BHA, we added 0.0304 g of solid HPA to 100 mL dH2O

2. Cerium (IV)

For Cerium Free Radicals: 100 mL solution of 2 mM HPA and 100 mL solution of Ce (IV).

For 100 mL of 2 mM HPA:

Weigh out 30.4mg of HPA

Add it into 100 mL DI water

For 100 mL of 2 mM Ce (IV)

Weigh out 109.6 mg of Ammonium Cerium Nitrate

Add that to 2.5 mL of 18M sulfuric acid

Add that solution to 97.5 mL of DI water

3. Fenton Chemistry

References

Fenton Chemistry Article
Fenton/DMPO (2016)
[Media:1-s2.0-S0891584996004327-main.pdf|Mason (1997) Fenton/DMPO]]

Fe2+ + H2O2 ---> OH• + phenol ---> phenoxyl radical

Solutions

1. HPA and hydrogen peroxide (100mL)

2mmolar HPA with 2mmolar hydrogen peroxide

 a. HPA made with 0.0300g of 152.015g/mol HPA
 b. 30 microliters of (30%) hydrogen peroxide was added

2. Iron(II) (100mL)

1M phosphoric acid with 1 milligram of Iron (II)

 a. 6.82mL Phosphoric acid was mixed with 93.18mL of RO water
 b. 1 mg of FeSO4 was added

ESR Results

These results were inconclusive at this time

Enzymatic Means