Difference between revisions of "Free Radical Generation"

Revision as of 21:39, 14 April 2016

The 1-electron oxidation of a phenol can be accomplished via chemical or enzymatic means.

To make a 2 mM solution of KMnO4, we added 0.0316g of KMnO4 solid to 100 mL dH2O

To make a 2 mM solution of BHA, we added 0.0304 g of solid HPA to 100 mL dH2O

For Cerium Free Radicals: 100 mL solution of 2 mM HPA and 100 mL solution of Ce (IV).

For 100 mL of 2 mM HPA:

Weigh out 30.4mg of HPA

Add it into 100 mL DI water

For 100 mL of 2 mM Ce (IV)

Weigh out 109.6 mg of Ammonium Cerium Nitrate

Add that to 2.5 mL of 18M sulfuric acid

Add that solution to 97.5 mL of DI water

Fe2+ + H2O2 ---> OH• + phenol ---> phenoxyl radical

1. HPA and hydrogen peroxide (100mL)

2mmolar HPA with 2mmolar hydrogen peroxide

 a. HPA made with 0.0300g of 152.015g/mol HPA
 b. 30 microliters of (30%) hydrogen peroxide was added

2. Iron(II) (100mL)

1M phosphoric acid with 1 milligram of Iron (II)

 a. 6.82mL Phosphoric acid was mixed with 93.18mL of RO water
 b. 1 mg of FeSO4 was added

These results were inconclusive at this time

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 [[Media: KMNO4.pdf|KMnO4]]
-To make a 2 mM solution of KMnO4, we added 0.03g of KMnO4 solid to 100 mL dH2O
+To make a 2 mM solution of KMnO4, we added 0.0316g of KMnO4 solid to 100 mL dH2O
 To make a 2 mM solution of BHA, we added 0.0304 g of solid HPA to 100 mL dH2O