Difference between revisions of "PChem312 f20 w13"
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4) Changes in both P and T, constant V | 4) Changes in both P and T, constant V | ||
:V<sub>i</sub>T<sub>i</sub>-->V<sub>f</sub>T<sub>f</sub> | :V<sub>i</sub>T<sub>i</sub>-->V<sub>f</sub>T<sub>f</sub> | ||
| + | |||
| + | ====Example Problem 1==== | ||
| + | :''(Please write out your complete solution and email to bes by next class period)'' | ||
| + | Consider a gas undergoing the following change under constant pressure (1.00 bar) conditions; calculate the change in entropy (ΔS): | ||
| + | V<sub>i</sub> = 10.0 L; T<sub>i</sub> = 298 K; T<sub>f</sub> = 398 K | ||
| + | |||
| + | ====Example Problem 2==== | ||
| + | :''(Please write out your complete solution and email to bes by next class period)'' | ||
| + | Consider a gas undergoing the following change under constant volume (10.0 L) conditions; calculate the change in entropy (ΔS): | ||
| + | P<sub>i</sub> = 1.00 bar; T<sub>i</sub> = 298 K; T<sub>f</sub> = 398 K | ||
===Wednesday, Nov 11, 2020=== | ===Wednesday, Nov 11, 2020=== | ||
Revision as of 14:52, 9 November 2020
Monday, Nov 9, 2020
We will now highlight how to calculate entropy (ΔS) for four processes involving ideal gases:
1) Reversible Isothermal Expansion or Compression
- ViTi-->VfTi
2) Constant P, V temperature change
- ViTi-->ViTf
- PiTi-->PiTf
3) Changes in both V and T, constant P
- ViTi-->VfTf
4) Changes in both P and T, constant V
- ViTi-->VfTf
Example Problem 1
- (Please write out your complete solution and email to bes by next class period)
Consider a gas undergoing the following change under constant pressure (1.00 bar) conditions; calculate the change in entropy (ΔS): Vi = 10.0 L; Ti = 298 K; Tf = 398 K
Example Problem 2
- (Please write out your complete solution and email to bes by next class period)
Consider a gas undergoing the following change under constant volume (10.0 L) conditions; calculate the change in entropy (ΔS): Pi = 1.00 bar; Ti = 298 K; Tf = 398 K