Difference between revisions of "Ch7 Lec6"
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(Created page with "(4/28/20, bes) Greetings, :I wanted to post this last lecture well before exam 3 (Friday, May 1st) so that you do not feel too rushed...review these notes as time permits. Th...") |
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==Multi-electron Energy Levels== | ==Multi-electron Energy Levels== | ||
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| − | |[[File:Energy level 04b.png| | + | |[[File:Energy level 04b.png|600px]] |
</div> | </div> | ||
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The figure above was presented in yesterday's notes...building upon this...please notice: | The figure above was presented in yesterday's notes...building upon this...please notice: | ||
:'''''The shift in the energy levels mixes up the order in which the orbitals are filled.''''' | :'''''The shift in the energy levels mixes up the order in which the orbitals are filled.''''' | ||
| + | ::- the 3d orbitals are now above the 4s orbitals | ||
| + | ::- the 4d orbitals are now above the 5s orbitals (not shown in figure) | ||
| + | ::- the 5d orbitals are now above the 6s orbitals (not shown in figure) | ||
| − | For boron (as previously discussed), it contains 5 electrons...with 2 electrons per orbital, then the electron configuration is: 1s<sup>2</sup> 2s<sup>2</sup> 2p<sup>1</sup>. | + | For boron (B) (as previously discussed), it contains 5 electrons...with 2 electrons per orbital, then the electron configuration is: 1s<sup>2</sup> 2s<sup>2</sup> 2p<sup>1</sup>. |
| − | :(Note: in WA i would ask that you enter the answer as, 1s2 2s2 2p1). | + | :''(Note: in WA i would ask that you enter the answer as, 1s2 2s2 2p1)''. |
| + | |||
| + | For carbon (C) (as previously discussed), it contains 6 electrons...with 2 electrons per orbital, then the electron configuration is: 1s<sup>2</sup> 2s<sup>2</sup> 2p<sup>2</sup>. | ||
| + | :''(Note: in WA i would ask that you enter the answer as, 1s2 2s2 2p2)''. | ||
| + | |||
| + | For neon (Ne), it contains 10 electrons...with 2 electrons per orbital, then the electron configuration is: 1s<sup>2</sup> 2s<sup>2</sup> 2p<sup>6</sup>. | ||
| + | :''(Note: in WA i would ask that you enter the answer as, 1s2 2s2 2p6)''. | ||
| + | |||
| + | For argon (Ar), it contains 18 electrons...with 2 electrons per orbital, then the electron configuration is: 1s<sup>2</sup> 2s<sup>2</sup> 2p<sup>6</sup> 3s<sup>2</sup> 3p<sup>6</sup>. | ||
| + | :''(Note: in WA i would ask that you enter the answer as, 1s2 2s2 2p6 3s2 3p6)''. | ||
| + | |||
| + | For calcium (Ca), it contains 20 electrons...with 2 electrons per orbital, then the electron configuration is: 1s<sup>2</sup> 2s<sup>2</sup> 2p<sup>6</sup> 3s<sup>2</sup> 3p<sup>6</sup> 4s<sup>2</sup>. | ||
| + | :''(Note: in WA i would ask that you enter the answer as, 1s2 2s2 2p6 3s2 3p6 4s2)''. | ||
Revision as of 15:12, 28 April 2020
(4/28/20, bes)
Greetings,
- I wanted to post this last lecture well before exam 3 (Friday, May 1st) so that you do not feel too rushed...review these notes as time permits. This is the last lecture for Chapter 7.
Multi-electron Energy Levels
|
The figure above was presented in yesterday's notes...building upon this...please notice:
- The shift in the energy levels mixes up the order in which the orbitals are filled.
- - the 3d orbitals are now above the 4s orbitals
- - the 4d orbitals are now above the 5s orbitals (not shown in figure)
- - the 5d orbitals are now above the 6s orbitals (not shown in figure)
For boron (B) (as previously discussed), it contains 5 electrons...with 2 electrons per orbital, then the electron configuration is: 1s2 2s2 2p1.
- (Note: in WA i would ask that you enter the answer as, 1s2 2s2 2p1).
For carbon (C) (as previously discussed), it contains 6 electrons...with 2 electrons per orbital, then the electron configuration is: 1s2 2s2 2p2.
- (Note: in WA i would ask that you enter the answer as, 1s2 2s2 2p2).
For neon (Ne), it contains 10 electrons...with 2 electrons per orbital, then the electron configuration is: 1s2 2s2 2p6.
- (Note: in WA i would ask that you enter the answer as, 1s2 2s2 2p6).
For argon (Ar), it contains 18 electrons...with 2 electrons per orbital, then the electron configuration is: 1s2 2s2 2p6 3s2 3p6.
- (Note: in WA i would ask that you enter the answer as, 1s2 2s2 2p6 3s2 3p6).
For calcium (Ca), it contains 20 electrons...with 2 electrons per orbital, then the electron configuration is: 1s2 2s2 2p6 3s2 3p6 4s2.
- (Note: in WA i would ask that you enter the answer as, 1s2 2s2 2p6 3s2 3p6 4s2).