Difference between revisions of "Ch5 Lec 3"

From MC Chem Wiki
Jump to navigation Jump to search
Line 29: Line 29:
  
 
Given:
 
Given:
:V= 22.4 L
+
:V= 22.414 L
:n = 1.00 moles
+
:n = 1.0000 moles
:T = 298 K
+
:T = 273.15 K
 
:R = from above...
 
:R = from above...
 
'''''Calculate the pressure in bar and make sure your work shows how the units cancel:'''''
 
'''''Calculate the pressure in bar and make sure your work shows how the units cancel:'''''
Line 37: Line 37:
  
  
 
+
As highlighted in
 
:[[File:Screen Shot 2020-03-29 at 11.20.53 AM.png|300px|thumb|center|from Crash Course]]
 
:[[File:Screen Shot 2020-03-29 at 11.20.53 AM.png|300px|thumb|center|from Crash Course]]

Revision as of 20:46, 30 March 2020

in progress...

Ideal Gas Law Equation (Sec 5.4)

from Crash Course

When combining all of the gas laws, Boyles, Charles', and Avogadro's we get the Ideal Gas Law Equation: As with any mathematical relationship/equation, if there are 5 variables (P, V, n, R, T) all you need to know is 4 of them and the 5th can be calculated.

R, the gas constant is equal to (depending on the units):

Screen Shot 2020-03-30 at 2.58.32 PM.png

Question 1

If given the following data, which gas constant would you use?

P = 1.12 atm
V= 2.45 L
n = 1.00 moles
T = 298 K
Answer: 0.082057 L*atm/(mol*K)

If the volume was not given in the question above, show how it can be calculated:

P = 1.12 atm
n = 1.00 moles
T = 298 K
R = 0.082057 l*atm/(mol*K)

Calculate V and make sure your work shows how the units cancel:

Question 2

If given the V, n, and T, which gas constant would you use if you want to calculate the pressure in "bar"?

Answer: 0.08314 L*bar/(mol*K)

Given:

V= 22.414 L
n = 1.0000 moles
T = 273.15 K
R = from above...

Calculate the pressure in bar and make sure your work shows how the units cancel:


As highlighted in

from Crash Course