Difference between revisions of "Ch5 Lec 3"

From MC Chem Wiki
Jump to navigation Jump to search
Line 15: Line 15:
 
:n = 1.00 moles
 
:n = 1.00 moles
 
:T = 298 K
 
:T = 298 K
<div align="right". Answer: 0.082057 L*atm/(mol*K)
+
<div align="right">Answer: 0.082057 L*atm/(mol*K)</div>
  
 
If the volume was not given in the question above, show how it can be calculated:
 
If the volume was not given in the question above, show how it can be calculated:
Line 22: Line 22:
 
:T = 298 K
 
:T = 298 K
 
:R = 0.082057 l*atm/(mol*K)
 
:R = 0.082057 l*atm/(mol*K)
'''''Calculate V= ? L'''''
+
'''''Calculate V and make sure your work shows how the units cancel:'''''
  
 +
====Question 2====
 +
If given the V, n, and T, which gas constant would you use if you want to calculate the pressure in "bar"?
 +
<div align="right">Answer: 0.08145 L*bar/(mol*K)</div>
 +
 +
Given:
 +
:V= 22.4 L
 +
:n = 1.00 moles
 +
:T = 298 K
 +
:R = from above...
 +
'''''Calculate the pressure in bar and make sure your work shows how the units cancel:'''''
  
  
  
If given the following data, which gas constant would you use?
 
:P = 1.12 atm
 
:V= 2.45 L
 
n = 1.00 moles
 
T = 298 K
 
<div align="right". Answer: 0.082057 L*atm/(mol*K)
 
  
 
:[[File:Screen Shot 2020-03-29 at 11.20.53 AM.png|300px|thumb|center|from Crash Course]]
 
:[[File:Screen Shot 2020-03-29 at 11.20.53 AM.png|300px|thumb|center|from Crash Course]]

Revision as of 20:11, 30 March 2020

in progress...

Ideal Gas Law Equation (Sec 5.4)

from Crash Course

When combining all of the gas laws, Boyles, Charles', and Avogadro's we get the Ideal Gas Law Equation: As with any mathematical relationship/equation, if there are 5 variables (P, V, n, R, T) all you need to know is 4 of them and the 5th can be calculated.

R, the gas constant is equal to (depending on the units):

Screen Shot 2020-03-30 at 2.58.32 PM.png

Question 1

If given the following data, which gas constant would you use?

P = 1.12 atm
V= 2.45 L
n = 1.00 moles
T = 298 K
Answer: 0.082057 L*atm/(mol*K)

If the volume was not given in the question above, show how it can be calculated:

P = 1.12 atm
n = 1.00 moles
T = 298 K
R = 0.082057 l*atm/(mol*K)

Calculate V and make sure your work shows how the units cancel:

Question 2

If given the V, n, and T, which gas constant would you use if you want to calculate the pressure in "bar"?

Answer: 0.08145 L*bar/(mol*K)

Given:

V= 22.4 L
n = 1.00 moles
T = 298 K
R = from above...

Calculate the pressure in bar and make sure your work shows how the units cancel:



from Crash Course