Difference between revisions of "Lab Molarity"
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+ | ====Example 7==== | ||
+ | :How many grams of NaCl are in 1.234 L of a 0.521 M NaCl solution? (''...follow the units...'') | ||
+ | ::::<write it out>...this is an extension of the problem above...first calculate moles then grans... | ||
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+ | <div align="center"> Answer = XXX grams NaCl</div> |
Revision as of 15:25, 20 March 2020
Welcome to your "sort of" first online lab. I would like to use this first lab activity to cover some additional lecture material and then follow it up with a short activity.
Section 4.5: Concentration of Solutions
Molarity (M)
You may have noticed in lab that many of the solutions we used had a label like "3M" to indicate the concentration of the solute in the solution. 3M means 3 molar or the molarity is 3. As you will see in your text the definition of molarity (M) is the moles of solute divided by liters of solution.
Example 1
- What is the molarity of a solution made by adding 1.23 moles of sodium chloride to 1 .00 L of water?
- <write this out>
Example 2
- What is the molarity of a solution made by adding 12.34 grams of sodium chloride to 1.000 L of water? (Note: you will need to calculate the molecular mass of NaCl...)
- <write this out>
- molecular mass of NaCl...
- 12.34 g of NaCl = ? moles of NaCl
- then calculate M = ?
Example 3
- What is the molarity of a solution made by adding 43.21 grams of sodium chloride to 1,234 mL of water?
- <write this out>
Example 4
- Molarity does not just apply to molecular or ionic compounds, but also ions. What is the molarity of Na+ and Cl- ions in a solution made by adding 43.21 grams of sodium chloride to 1,234 mL of water?
- Given that you have completed Example 3, we know that the molarity of NaCl = 0.5992 M
Notice that we use brackets around the chemical formula, ie. [NaCl] to mean "molarity of NaCl"...this is shorthand notation.
Example 5
- What is the molarity of Ca2+ and Cl- ions in a solution made by adding 34.2 grams of calcium chloride to 543 mL of water?
- <write it out>
The above examples are considered fairly basic. In these problems above you were given either moles or grams of solute and the final volume of the solution and asked to calculate the molarity. There are 3 values, grams/moles (either one), volume of solution, and molarity; as with any math problem, if given any two fo the three, you can solve for the other.
Example 6
- How many moles of NaCl are in 1.234 L of a 0.521 M NaCl solution? (...follow the units...)
- <write it out>...here is how i did it...
Example 7
- How many grams of NaCl are in 1.234 L of a 0.521 M NaCl solution? (...follow the units...)
- <write it out>...this is an extension of the problem above...first calculate moles then grans...