Difference between revisions of "PChem312 f20 w11"
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Study Example Problem 4.2 for calculation details... | Study Example Problem 4.2 for calculation details... | ||
:ΔH°(298K) = -92.3 kJ/mol HCl | :ΔH°(298K) = -92.3 kJ/mol HCl | ||
− | : temp correction = 2.8 kJ/mol HCl (mainly due to the | + | : temp correction = -2.8 kJ/mol HCl |
+ | :ΔH°(298K) = -95.1 kJ/mol HCl | ||
+ | :'''''Explanation: this difference is mainly due to the change in the heat capacity of Cl<sub>2</sub> gas; the product HCl has a lower heat capacity than Cl<sub>2</sub>...so heat produced from the reaction cannot be contained in the products hence it is given off...ie. higher ΔH°(1450K).''''' | ||
:[[File:ExProb4_2.png|600px]] | :[[File:ExProb4_2.png|600px]] | ||
+ | |||
+ | ====Additional worksheet==== | ||
+ | :[[Media:Self_heating_can.pdf|Self-Heating Can]] | ||
===Weds, Oct 28, 2020=== | ===Weds, Oct 28, 2020=== | ||
− | + | ====Sec. 4.6 (supplental)==== | |
+ | Differential Scanning Calorimetry (DCS) | ||
===Thurs, Oct 29th, 2020=== | ===Thurs, Oct 29th, 2020=== |
Latest revision as of 15:31, 29 October 2020
Monday, Oct 26, 2020
Announcement: Exam 2, Thursday, Oct 29th (Ch 3 and 4)
Sec 4.4
Temperature dependence of reaction enthalpies...
This problem involves 2 parts:
- 1) ΔH°(298K) can be calculated via heats of formation (ΔH°f)
- 2) the second part requires that you look up the Cp,m values from table 2.5...
Study Example Problem 4.2 for calculation details...
- ΔH°(298K) = -92.3 kJ/mol HCl
- temp correction = -2.8 kJ/mol HCl
- ΔH°(298K) = -95.1 kJ/mol HCl
- Explanation: this difference is mainly due to the change in the heat capacity of Cl2 gas; the product HCl has a lower heat capacity than Cl2...so heat produced from the reaction cannot be contained in the products hence it is given off...ie. higher ΔH°(1450K).
Additional worksheet
Weds, Oct 28, 2020
Sec. 4.6 (supplental)
Differential Scanning Calorimetry (DCS)
Thurs, Oct 29th, 2020
- Exam 2, Ch 3 and 4.
Friday, Oct 30th, 2020
- no class