Difference between revisions of "Free Radical Generation"
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=='''Chemical Means'''== | =='''Chemical Means'''== | ||
| − | 1 | + | ===1. KMnO4=== |
| + | [[Media: KMNO4.pdf|KMnO4]] | ||
| + | |||
| + | To make a 2 mM solution of KMnO4, we added 0.0316g of KMnO4 solid to 100 mL dH2O | ||
| + | |||
| + | To make a 2 mM solution of BHA, we added 0.0304 g of solid HPA to 100 mL dH2O | ||
===2. Cerium (IV)=== | ===2. Cerium (IV)=== | ||
For Cerium Free Radicals: | For Cerium Free Radicals: | ||
100 mL solution of 2 mM HPA and 100 mL solution of Ce (IV). | 100 mL solution of 2 mM HPA and 100 mL solution of Ce (IV). | ||
| + | |||
For 100 mL of 2 mM HPA: | For 100 mL of 2 mM HPA: | ||
| + | |||
Weigh out 30.4mg of HPA | Weigh out 30.4mg of HPA | ||
| + | |||
Add it into 100 mL DI water | Add it into 100 mL DI water | ||
| + | |||
For 100 mL of 2 mM Ce (IV) | For 100 mL of 2 mM Ce (IV) | ||
| + | |||
Weigh out 109.6 mg of Ammonium Cerium Nitrate | Weigh out 109.6 mg of Ammonium Cerium Nitrate | ||
| + | |||
Add that to 2.5 mL of 18M sulfuric acid | Add that to 2.5 mL of 18M sulfuric acid | ||
| + | |||
Add that solution to 97.5 mL of DI water | Add that solution to 97.5 mL of DI water | ||
===3. Fenton Chemistry=== | ===3. Fenton Chemistry=== | ||
| − | [[Media: Fenton.pdf|Fenton | + | References |
| + | :[[Media: Fenton.pdf|Fenton/Phenol (2005)]] | ||
| + | :[[Media:Water_Res_2016.pdf|Fenton/DMPO (2016)]] | ||
| + | :[[Media:1-s2.0-S0891584996004327-main.pdf|Mason (1997) Fenton/DMPO]] | ||
| + | |||
| + | Fe2+ + H2O2 ---> OH• + phenol ---> phenoxyl radical | ||
====Solutions==== | ====Solutions==== | ||
| + | 1. HPA and hydrogen peroxide (100mL) | ||
| + | |||
| + | 2 mmolar HPA with 2 mmolar hydrogen peroxide | ||
| + | |||
| + | a. HPA made with 0.0300g of 152.015g/mol HPA | ||
| + | b. 30 microliters of (30%) hydrogen peroxide was added | ||
| + | |||
| + | 2. Iron(II) (100mL) | ||
| + | |||
| + | 1M phosphoric acid with 1 milligram of Iron (II) | ||
| + | |||
| + | a. 6.82 mL Phosphoric acid was mixed with 93.18 mL of RO water | ||
| + | b. 1 mg of FeSO4 was added | ||
| + | |||
| + | ====ESR Results==== | ||
| + | These results were inconclusive at this time | ||
==Enzymatic Means== | ==Enzymatic Means== | ||
Latest revision as of 19:21, 6 June 2019
The 1-electron oxidation of a phenol can be accomplished via chemical or enzymatic means.
Chemical Means
1. KMnO4
To make a 2 mM solution of KMnO4, we added 0.0316g of KMnO4 solid to 100 mL dH2O
To make a 2 mM solution of BHA, we added 0.0304 g of solid HPA to 100 mL dH2O
2. Cerium (IV)
For Cerium Free Radicals: 100 mL solution of 2 mM HPA and 100 mL solution of Ce (IV).
For 100 mL of 2 mM HPA:
Weigh out 30.4mg of HPA
Add it into 100 mL DI water
For 100 mL of 2 mM Ce (IV)
Weigh out 109.6 mg of Ammonium Cerium Nitrate
Add that to 2.5 mL of 18M sulfuric acid
Add that solution to 97.5 mL of DI water
3. Fenton Chemistry
References
Fe2+ + H2O2 ---> OH• + phenol ---> phenoxyl radical
Solutions
1. HPA and hydrogen peroxide (100mL)
2 mmolar HPA with 2 mmolar hydrogen peroxide
a. HPA made with 0.0300g of 152.015g/mol HPA b. 30 microliters of (30%) hydrogen peroxide was added
2. Iron(II) (100mL)
1M phosphoric acid with 1 milligram of Iron (II)
a. 6.82 mL Phosphoric acid was mixed with 93.18 mL of RO water b. 1 mg of FeSO4 was added
ESR Results
These results were inconclusive at this time